I'm a new joiner, I hope I enjoy with this forum.
I have a problem, look this picture:
Maybe somebody can solve this with simply way? help me...
Thnx..
Note : AD = 8
BC = 10
EF = 4
CD = .......
ACD not a rectangle, but rigt triangle, same like BCD
There is no other information. just like that.
EF is perpendicular form cross of AD and BC.
hm... it's difficult for me..
I get this question from old book - that I have loose it
but I remember this question.
the information just like that.
ACD not a rectangle, but rigt triangle, same like BCD
There is no other information. just like that.
EF is perpendicular form cross of AD and BC.
hm... it's difficult for me..
I get this question from old book - that I have loose it
but I remember this question.
the information just like that.