I'm a new joiner, I hope I enjoy with this forum.

I have a problem, look this picture:

Maybe somebody can solve this with simply way? help me...

Thnx..

Note : AD = 8

BC = 10

EF = 4

CD = .......

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- November 13th 2008, 06:43 PMosana412Help me, this problem make me 'confuse'
I'm a new joiner, I hope I enjoy with this forum.

I have a problem, look this picture:

Maybe somebody can solve this with simply way? help me...

Thnx..

Note : AD = 8

BC = 10

EF = 4

CD = ....... - November 15th 2008, 05:48 PMNacho
Don`t has more information?

for example that triangle ACD is rectangle - November 17th 2008, 10:58 PMosana412
ACD not a rectangle, but rigt triangle, same like BCD

There is no other information. just like that.

EF is perpendicular form cross of AD and BC.

hm... it's difficult for me..

I get this question from old book - that I have loose it :(

but I remember this question.

the information just like that. - November 17th 2008, 11:07 PMosana412
ACD not a rectangle, but rigt triangle, same like BCD

There is no other information. just like that.

EF is perpendicular form cross of AD and BC.

hm... it's difficult for me..

I get this question from old book - that I have loose it :(

but I remember this question.

the information just like that. :)