# Help me, this problem make me 'confuse'

• Nov 13th 2008, 07:43 PM
osana412
Help me, this problem make me 'confuse'
I'm a new joiner, I hope I enjoy with this forum.

I have a problem, look this picture:

Maybe somebody can solve this with simply way? help me...
Thnx..

BC = 10
EF = 4
CD = .......
• Nov 15th 2008, 06:48 PM
Nacho

for example that triangle ACD is rectangle
• Nov 17th 2008, 11:58 PM
osana412
ACD not a rectangle, but rigt triangle, same like BCD
There is no other information. just like that.
EF is perpendicular form cross of AD and BC.

hm... it's difficult for me..
I get this question from old book - that I have loose it :(
but I remember this question.
the information just like that.
• Nov 18th 2008, 12:07 AM
osana412
ACD not a rectangle, but rigt triangle, same like BCD
There is no other information. just like that.
EF is perpendicular form cross of AD and BC.

hm... it's difficult for me..
I get this question from old book - that I have loose it :(
but I remember this question.
the information just like that. :)