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Math Help - please help

  1. #1
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    please help

    Two chords KV and QR of circle O are perpendicular at oint P, with PQ = 6 and PR = 8. If the radius of circle O is √65, find KP and PV.
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  2. #2
    MHF Contributor red_dog's Avatar
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    Let OM\perp RQ and ON\perp KV.
    RQ=14\Rightarrow MQ=7\Rightarrow ON=MP=MQ-PQ=7-6=1
    In the triangle OMQ: OM=\sqrt{OQ^2-MQ^2}=\sqrt{65-49}=\sqrt{16}=4\Rightarrow PN=4
    In the triangle ONK: KN=\sqrt{OK^2-ON^2}=\sqrt{65-1}=8
    Then KP=KN-PN=8-4=4 and PV=KV-KP=16-4=12
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  3. #3
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    Red dog your a genius any chance you can help with my problem?
    http://www.mathhelpforum.com/math-he...arger-one.html
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  4. #4
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    thank you very much red dog!
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