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**IDontunderstand** In triangle ABC, AD and DE are angle bisectors and <=76 What is the measure of <ADC. If AD bisects angle A, what angle does DE bisect?

So I have a Triangle that is ABC, Angle A is Bisected by AD

Angle C is Bisected By CD. Angle C cannot possibly be bisected by CD.

I am told that B is 76 degrees, Since A and C are bisected I have a triangle ACD and I want the measure of D. There are two angles at D.

If I find the measure of angle BCA and BAC, take half of those and subtract from 180 that will give me angle D, But if I am not told that

triangle ABC is isosceles how can I conclude the measure of angle BCA and BAC, with the information that I am given that is the only way to find the angle. So advise would be great, sorry I dont have a picture