http://i299.photobucket.com/albums/m...07/Q12jpeg.jpgHi everyone, I know it doesn't look it but AB = BC = CD. The triangle is an equilateral and you need to find the ratio of the area of the triangle to the area of the 2/3 ring sorrounding it.

On the Oxford Physics Aptitude Test, this was the last question in the maths section.

I got

$\displaystyle

\frac{9\sqrt{3}}{8\pi(3+2\sqrt{3})}

$