Can't seem to work out this question. (x+3)^2 + 24^2 = (AC)^2
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AB, AC and BC are all tangents so AD = AE = x BD = BF = 3 FC = EC = 24 - 3 = 21 So AC = AE + EC = x + 21 So equation becomes (x + 3)^2 + 24^2 = (x + 21)^2 Can you solve it now?
Thanks Glaysher, of course now that you have done it, I can. Mental Note.. *Always check for tangents*
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