Thread: A Hint needed...stuck

Can't seem to work out this question.

(x+3)^2 + 24^2 = (AC)^2

AB, AC and BC are all tangents so

AD = AE = x

BD = BF = 3

FC = EC = 24 - 3 = 21

So AC = AE + EC = x + 21

So equation becomes

(x + 3)^2 + 24^2 = (x + 21)^2

Can you solve it now?

Thanks Glaysher, of course now that you have done it, I can.

Mental Note..

*Always check for tangents*