Can't seem to work out this question.
(x+3)^2 + 24^2 = (AC)^2
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AB, AC and BC are all tangents so
AD = AE = x
BD = BF = 3
FC = EC = 24 - 3 = 21
So AC = AE + EC = x + 21
So equation becomes
(x + 3)^2 + 24^2 = (x + 21)^2
Can you solve it now?
Thanks Glaysher, of course now that you have done it, I can.
Mental Note.. *Always check for tangents*
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