Can't seem to work out this question.

(x+3)^2 + 24^2 = (AC)^2

http://img80.imageshack.us/img80/9751/121212ql1.jpg

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- Sep 23rd 2006, 11:10 PMclassicstringsA Hint needed...stuck
Can't seem to work out this question.

(x+3)^2 + 24^2 = (AC)^2

http://img80.imageshack.us/img80/9751/121212ql1.jpg - Sep 23rd 2006, 11:27 PMGlaysher
AB, AC and BC are all tangents so

AD = AE = x

BD = BF = 3

FC = EC = 24 - 3 = 21

So AC = AE + EC = x + 21

So equation becomes

(x + 3)^2 + 24^2 = (x + 21)^2

Can you solve it now? - Sep 24th 2006, 12:07 AMclassicstrings
Thanks Glaysher, of course now that you have done it, I can.

Mental Note..

***Always check for tangents***