Let the perpendicular BE intersects AD at O.

An intercept EF equal in length of EO is cut from EA. F,O are joined and prodced to intersect the produced ED at G.

THe triangle EFO is an rt angle isosceles triangle where EO = EF and angle FEO = 90 deg

Hence ang EFG = ang EFO = 45 deg

So the exterior angle of the triangle EFG ie angle CEG = angle EFG + angle FGE.

ie angle CED is greater than 45 deg.

Is there any thing Wrong? if any please comment.