Math Help - Help with measures of angles

1. Help with measures of angles

2. Originally Posted by dgenerationx2
$m\angle 3=90^{\circ}$ - A line perpendicular to one of two perpendicular lines is perpendicular to the other one also.

$m\angle 4=125^{\circ}$ - This angle is vertical to angle 1. Vertical angles are congruent.

$m\angle 5=125^{\circ}$ - Angle 1 and angle 5 are congruent because they are alternate interior angles.

$m\angle 6=55^{\circ}$ - Angles 5 and 6 make up a linear pair and are supplementary.

$m\angle 7=125^{\circ}$ - Angles 7 and 5 are vertical angles so they are congruent.

3. Help With Special Right Triangles

Here is my problem. I will send it in attachments but if you can't see the triangles in the attachment i will explain it.

Fill in the missing side lengths and angle measures for each special right triangle below.

The 1st triangle is A 30-60-90 degree Triangle. the 30-60 Side Length is 8. But Whta Are The Others.

The 2nd Triangle is A 40-40-90 degree Triangle. The 40-90 Side Length is 6. Wouldn't that make the other 40-90 side A 6 (Is This Right). So what is the missing side.

Help. Please. I Will Be Very Grateful.

4. Math lesson help

can anybody see the pictures needed to answer this lesson because I can't see it. it is in the attachments

5. Originally Posted by dgenerationx2
Here is my problem. I will send it in attachments but if you can't see the triangles in the attachment i will explain it.

Fill in the missing side lengths and angle measures for each special right triangle below.

(1) If the hypotenuse of a 30-60-90 right triangle = 8, then the short side (side opposite the 30 degree angle) is half of that or 4. The long side (side opposite the 60 degree angle) = the short side times the square root of 3 or $4\sqrt{3}$
(1) A 45-45-90 right triangle is isosceles. If one leg = 6, so does the other. The hypotenuse is equal to a leg times the square root of 2 or $6\sqrt{2}$