Hello, alaricepent!

Make a sketch, then baby-talk your way through it . . .

Suppose the length of a rectangle is twice the width.

If we increase both the width and length of the rectangle by 2 units,

the area is increased by 34 square units.

Find the width of the rectangle.

. . Code:

2x
*-------------*
| |
x | | x
| |
*-------------*
2x

Let = width

Then = length.

. . The area is: .

Code:

2x+2
*-------------*---*
| : |
| : |
x+2 | : | x+2
* - - - - - - * |
| |
*-----------------*
2x+2

Now = width

and = length

. . The area is: .

The new area is 34 more than the original area:

. .

So we have: .

The width is 5 . . . answer (d)