1. ## Inequality Proof

Hi, I think this is part of Euclidian Geometry because the term started off with it. I actually posted this in the Urgent hw help section but there was no reply and I am in great need of help right now. I am so sorry for reposting but I really need help with this problem and it's due tomorrow.

How would you prove this problem? And can you please explain. I really don't know how to do it.

The diagram can be seen here:
http://offtype.net/image_2456233493507.g...

Given: AB=AC;
Line seg. BC bisects angle ABC;
Line seg. DE bisects angle ADB

Prove: BE>DE

By "prove" means it's suppose to be in statements/reasons. Thank you.

2. the question should be BE bisects angle ABC and D is any point on BC other than C.

the exterior angle ADB is greater than interior angle ACD of the triangle ACD . again ang ACD = ang ABD ( since AB =AC)

hence ang EBD (which is half of ang ABD) is less than ang EDB (which is half of ang ADB)

therefore BE is greater than DE

Are you satisfied? pl intimate.