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Hi and Help please!!
I have a test tomorrow first period in geometry and I am stumped on these two problems on the review sheet.
a) Find QD if QE=11+20 and QD=400 -10 _______________
a-2 a+3 Q E D
E is the midpoint
b) Angle 3 and 4 are supplementary. Find the measure of angle 3
m>3=78+360 and m>4= 360 + 32
y y-3
Thank you to anyone that can help me. I am so tired, I can't see straight!
is this supposed to be ...Quote:
Originally Posted by surfside4us@nycap.rr.com
$\displaystyle QE = 11 + \frac{20}{a-2}$
$\displaystyle QD = \frac{400}{a+3} - 10$
or something else?
same question ...Quote:
b) Angle 3 and 4 are supplementary. Find the measure of angle 3
m>3=78+360 and m>4= 360 + 32
y y-3
$\displaystyle m\angle{3} = 78 + \frac{360}{y}$
$\displaystyle m\angle{4} = \frac{360}{y-3} + 32$
???
QE=11+ 20/(a-2) QD=400/(a+3) -10
E is midpoint of line QED
2nd headache question:m>3=78+360/y andm>4=360/y-3 +32
Angle 3 and angle 4 are supplementary
Sorry I typed wrong, I am beat. This test is a make it or break it for me in this course. Any help would be so appreciated.
