Thread: Inscribe Square.

I am having a problem with this problem...

the exact problem is,

"Inscribe a square in a given sector of a circle. Two vertices of the square are required to lie on the arc, one vertex on each of the two sides of the central angle of the sector."


I got the inscribe square where our central angle is 180.

But what about when central angle is >180, <180.

Thanks everyone

Originally Posted by joesmith13610

I am having a problem with this problem...

the exact problem is,

"Inscribe a square in a given sector of a circle. Two vertices of the square are required to lie on the arc, one vertex on each of the two sides of the central angle of the sector."


I got the inscribe square where our central angle is 180.

But what about when central angle is >180, <180.

Thanks everyone

1. Draw an arbitrary square, symmetric to the angle bisector of the central angle of the sector, with 2 vertices placed on the legs of the central angle. See attachment: The red square.

2. Use central dilation(?) to get the final result: The blue square.

3. In my opinion this method should work with every central angle.

thank you earboth. I appreciate your help, now on forth to the proof.


thanks again.