I am having a problem with this problem...
the exact problem is,
"Inscribe a square in a given sector of a circle. Two vertices of the square are required to lie on the arc, one vertex on each of the two sides of the central angle of the sector."
I got the inscribe square where our central angle is 180.
But what about when central angle is >180, <180.
1. Draw an arbitrary square, symmetric to the angle bisector of the central angle of the sector, with 2 vertices placed on the legs of the central angle. See attachment: The red square.
Originally Posted by joesmith13610
2. Use central dilation(?) to get the final result: The blue square.
3. In my opinion this method should work with every central angle.
thank you earboth. I appreciate your help, now on forth to the proof.