Let ABCD be a cyclic quadrilateral with AB=BC. If P is a point on CD such that AP=PB=BA, prove that AD=R, the circumradius of $\displaystyle \triangle ABC$.

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- Oct 22nd 2008, 09:17 AMalexmahoneCyclic quadrilateral
Let ABCD be a cyclic quadrilateral with AB=BC. If P is a point on CD such that AP=PB=BA, prove that AD=R, the circumradius of $\displaystyle \triangle ABC$.