google is your friend. see here. that should help
thanks ear but i have to build a structure
and the slant is on the roof from right to left is going downhill
so the 2 sides of the structure will be equal and 5.6 metres height with the slant tallest part and 4 metres in length and 4 metres in height.
the front is 3.8 metres length by 4 metres height.
and the back of the structure the tallest part is 3.8 metres length and 5.6 metres height.
the volume i got was 72.96 metres cubed.
how to find the surface area of this structure thankyou.
If I understand your sketch correctly your structure is a prism. The base area seems to be a rectangle and it looks like as if the "roof" of the prism has a sharp bend.
Divide this prism into 3 different solids:
1. A prism with a rectangle as the base area and the height of 4 m
2. A prism with a right triangle as the base area and the height of 1.6 m
3. A pyramid with the top T and the vertical rectangle as base area.
According to these settings (merely guessing!) the volume is:
The surface of the complete structure is:
1. base area
2. two rectangles
3. two trapezii
4. one right triangle, one acute triangle
To calculate the area of the last triangle I calculated the lengths of the sides first (use Pythagorean theorem)
Calculate the angle at T:
And now I hope that this reply doesn't come too late...