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Math Help - Help with crazy triangle's measurments!!

  1. #1
    Newbie Alchemist9's Avatar
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    Georgia
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    Unhappy Help with crazy triangle's measurments!!

    This is due tomorrow!And I have stared at the sheet of paper for two days not having a clue what it means.
    I do good with equations but not this!.

    Please help me!

    This is the figure:
    ImageShack - Hosting :: mathproblemgk4.jpg

    I need to know the measurements of angles a through m!
    And I just don't think I have enough information on the sheet to do it.

    Help?please?

    thanks.
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  2. #2
    MHF Contributor
    Joined
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    Quote Originally Posted by Alchemist9 View Post
    This is due tomorrow!And I have stared at the sheet of paper for two days not having a clue what it means.
    I do good with equations but not this!.

    Please help me!

    This is the figure:
    ImageShack - Hosting :: mathproblemgk4.jpg

    I need to know the measurements of angles a through m!
    And I just don't think I have enough information on the sheet to do it.

    Help?please?

    thanks.
    I think the information is enough to solve for all of the angles.

    It would be too much explanations if I would explain them the way I do, so I will not explain them the way I normally do. :-)
    I just hope ypou know he relationships of angles
    >>>around parallel lines and their transversal lines
    >>>in a straight line
    >>>inside a triangle
    >>>opposite equal sides of an isosceles triangle

    a = 180 -126 = 54 deg
    b = 126 deg
    c = 180 -126 = 54 deg
    d = [180 -(180-54)] /2 = 27 deg
    e = 180 -27 = 153 deg
    f = 180 -126 = 54 deg
    g = 180 -54 -54 = 72 deg
    h = 180 -c -f = 180 -54 -54 = 72 deg
    i = 180 -[180 -27 -72] = 99 deg
    j = 180 -54 -g = 180 -54 -72 = 54 deg
    k = ?

    I think the topmost ray is not parallel to the other two rays below it.
    So k can de solved from the isosceles triangle whose apex is 54 degrees ....the one that is supplementary to b.
    So, k = (1/2)(180 -54) = 63 deg

    L = (1/2)(180 -63) = 58.5 deg
    m = 180 -L = 121.5 deg
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  3. #3
    Newbie Alchemist9's Avatar
    Joined
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    Georgia
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    Quote Originally Posted by ticbol View Post
    I think the information is enough to solve for all of the angles.

    It would be too much explanations if I would explain them the way I do, so I will not explain them the way I normally do. :-)
    I just hope ypou know he relationships of angles
    >>>around parallel lines and their transversal lines
    >>>in a straight line
    >>>inside a triangle
    >>>opposite equal sides of an isosceles triangle

    a = 180 -126 = 54 deg
    b = 126 deg
    c = 180 -126 = 54 deg
    d = [180 -(180-54)] /2 = 27 deg
    e = 180 -27 = 153 deg
    f = 180 -126 = 54 deg
    g = 180 -54 -54 = 72 deg
    h = 180 -c -f = 180 -54 -54 = 72 deg
    i = 180 -[180 -27 -72] = 99 deg
    j = 180 -54 -g = 180 -54 -72 = 54 deg
    k = ?

    I think the topmost ray is not parallel to the other two rays below it.
    So k can de solved from the isosceles triangle whose apex is 54 degrees ....the one that is supplementary to b.
    So, k = (1/2)(180 -54) = 63 deg

    L = (1/2)(180 -63) = 58.5 deg
    m = 180 -L = 121.5 deg

    Wow.thanks.soooooooo much <33
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  4. #4
    Newbie Alchemist9's Avatar
    Joined
    Oct 2008
    From
    Georgia
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    Quote Originally Posted by ticbol View Post
    I think the information is enough to solve for all of the angles.

    It would be too much explanations if I would explain them the way I do, so I will not explain them the way I normally do. :-)
    I just hope ypou know he relationships of angles
    >>>around parallel lines and their transversal lines
    >>>in a straight line
    >>>inside a triangle
    >>>opposite equal sides of an isosceles triangle

    a = 180 -126 = 54 deg
    b = 126 deg
    c = 180 -126 = 54 deg
    d = [180 -(180-54)] /2 = 27 deg
    e = 180 -27 = 153 deg
    f = 180 -126 = 54 deg
    g = 180 -54 -54 = 72 deg
    h = 180 -c -f = 180 -54 -54 = 72 deg
    i = 180 -[180 -27 -72] = 99 deg
    j = 180 -54 -g = 180 -54 -72 = 54 deg
    k = ?

    I think the topmost ray is not parallel to the other two rays below it.
    So k can de solved from the isosceles triangle whose apex is 54 degrees ....the one that is supplementary to b.
    So, k = (1/2)(180 -54) = 63 deg

    L = (1/2)(180 -63) = 58.5 deg
    m = 180 -L = 121.5 deg
    Wait . . . I thought angles measurements couldn't be decimals?
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  5. #5
    MHF Contributor
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    Quote Originally Posted by Alchemist9 View Post
    Wait . . . I thought angles measurements couldn't be decimals?
    Who said?

    If there are no rules against it, then angles can be in decimals, like in any measurement.
    If the rule is for angles not to be in decimals but in degrees, minutes and seconds,
    then, 0.5 deg = 30 minutes.
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