I think the information is enough to solve for all of the angles.

It would be too much explanations if I would explain them the way I do, so I will not explain them the way I normally do. :-)

I just hope ypou know he relationships of angles

>>>around parallel lines and their transversal lines

>>>in a straight line

>>>inside a triangle

>>>opposite equal sides of an isosceles triangle

a = 180 -126 = 54 deg

b = 126 deg

c = 180 -126 = 54 deg

d = [180 -(180-54)] /2 = 27 deg

e = 180 -27 = 153 deg

f = 180 -126 = 54 deg

g = 180 -54 -54 = 72 deg

h = 180 -c -f = 180 -54 -54 = 72 deg

i = 180 -[180 -27 -72] = 99 deg

j = 180 -54 -g = 180 -54 -72 = 54 deg

k = ?

I think the topmost ray is not parallel to the other two rays below it.

So k can de solved from the isosceles triangle whose apex is 54 degrees ....the one that is supplementary to b.

So, k = (1/2)(180 -54) = 63 deg

L = (1/2)(180 -63) = 58.5 deg

m = 180 -L = 121.5 deg