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Math Help - Physics which involves SIMPLE GEOMETRY, really urgent, please help!

  1. #1
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    Physics which involves SIMPLE GEOMETRY, really urgent, please help!

    I've attached a picture which include the question -- I found it on the net, and it's exactly the same as my homework.

    I've got hints on this before, but I don't understand how to calculate the length, so please show me how if you can
    Last edited by KiyoEtAlice; October 14th 2008 at 12:53 AM.
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    Quote Originally Posted by KiyoEtAlice View Post
    I've attached a picture which include the question -- I found it on the net, and it's exactly the same as my homework.

    I've got hints on this before, but I don't understand how to calculate the length, so please show me how if you can
    Actually you are dealing with a right triangle. (see attachment)

    According to Euklid's theorem you have:

    \left(\dfrac d2 \right)^2 = h \cdot (2R-h)

    Solve for R.
    Attached Thumbnails Attached Thumbnails Physics which involves SIMPLE GEOMETRY, really urgent, please help!-euklid_theor3.png  
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    thanks but can you tell me what "d" value is supposed to be? I think I got things mized up. "h" is 5 for the ball right?
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    Quote Originally Posted by KiyoEtAlice View Post
    thanks but can you tell me what "d" value is supposed to be? I think I got things mized up. "h" is 5 for the ball right?
    The text of the problem says: "... They both travel 10 m in the x-direction. ..." So here you have d = 10 m
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    Quote Originally Posted by earboth View Post
    The text of the problem says: "... They both travel 10 m in the x-direction. ..." So here you have d = 10 m

    Okay Thanks!

    I've done it, and my R for each of the cases come out differently, is this supposed to happen?
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    Quote Originally Posted by KiyoEtAlice View Post
    Okay Thanks!

    I've done it, and my R for each of the cases come out differently, is this supposed to happen?
    of course. The curve of the ball is much more bent than the curve of the bullet. Thus the radius connected to the curve of the ball is much smaller than the radius of the curve of the bullet.

    I've got r_{ball} = 5\ m and r_{bullet} = 25000\ m
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    Quote Originally Posted by earboth View Post
    of course. The curve of the ball is much more bent than the curve of the bullet. Thus the radius connected to the curve of the ball is much smaller than the radius of the curve of the bullet.

    I've got r_{ball} = 5\ m and r_{bullet} = 25000\ m
    Okay, thanks! I've got the same result. Thanks a lot!
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