In the triangle ABC, the point P lies on the side AC such that angle BPC = angle ABC. Show that the triangles BPC and ABC are similar.
If AB = 4cm , Ac = 8cm , BP = 3cm , find the area of the triangle BPC.
For part two, use their similar properties.
AB /AC = BP /BC
BC = (8*3)/4 = 6
AB /BC = BP /PC
PC = (6*3)/4 = 4.5
You have now the 3 sides of triangle BPC.
Use the Heron's formula for the area.