Please solve this question using heron's formula..

The perimeter of an isosceles triangle is 42cm and its base is (3/2)times each of the equal sides.Find the length of each side of the triangle,area of the triangle and height of the triangle.

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- October 8th 2008, 07:22 AMrickymylvplease solve
Please solve this question using heron's formula..

The perimeter of an isosceles triangle is 42cm and its base is (3/2)times each of the equal sides.Find the length of each side of the triangle,area of the triangle and height of the triangle. - October 8th 2008, 12:00 PMearboth
Let x denote the length of one leg. Then the perimeter of the triangle is:

That means the triangle has the side length:

a = 12, b = 12, c = 18 (c is the base)

1. Calculate the area by Heron's formula:

The half perimeter is s = 21

2.**The**height of the trinagle. Actually there are (normally) three heights in every triangle. Here 2 of the three heights are equal.

From you get

Plug in the values you know to calculate the heights:

- October 8th 2008, 04:38 PMfranckherve1
i agree with the x=12,x=12,b=18...the h goes through the middle of b

so to get h..you have to take half of b and one side of the triangle and use pytagore

12(squared)=9(squared)+h(squared)

h(squared)=12(squared)-9(squared)

h(squared)=144-81

h(squared)=63

h=3(square root)7

to get the area b*h/2

18*3(squared root)7/2

=54(squared root)7/2