ABCD is a rhombus with diagonals AC = 12 cm and BD = 9 cm. Construct ABCD using a ruler and compasses.
Could someone please instruct me on how to do this construction?
2. Construct the perpendicular bisector of AC using 2 circles with center at A and C, radius > half of AC
3. Draw a circle with r = 4.5 cm around the midpoint of AC.
4. Intersection points of this circle with the perpendicular bisector are B and D.
5. Complete the rhombus.
EDIT: I've attached the construction.