The area of a square is 9. If this square and an equilateral triangle have equal perimeters, find the length of one side of the triangle.
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Originally Posted by magentarita The area of a square is 9. If this square and an equilateral triangle have equal perimeters, find the length of one side of the triangle. Area of square = 9 $\displaystyle A=s^2$ $\displaystyle 9=s^2$ $\displaystyle s=3$ (side of square) Perimeter of Square = 4(3) = 12 Perimeter of equilateral triangle = 12 P = 3s 12 = 3s s = 4 (side of triangle)
Originally Posted by masters Area of square = 9 $\displaystyle A=s^2$ $\displaystyle 9=s^2$ $\displaystyle s=3$ (side of square) Perimeter of Square = 4(3) = 12 Perimeter of equilateral triangle = 12 P = 3s 12 = 3s s = 4 (side of triangle) Another wonderful reply. Thanks
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