In the given figure i need to find AC and AB.
CD= 6 cm
BD = 8 cm
Radius = 4 cm
Cant figure this thing out.
Draw OX and OY perpendicular to AC and AB, respectively, at their points of tangency.
Center O is the incenter of the inscribed circle found by the intersection of the three angle bisectors. Thus,
Angle ACO = Angle BCO
Angle CAO = Angle BAO
Angle ABO = Angle CBO
CD = CX and BD = BY, since tangents to a circle from an external point are equal.
CX = 6
BY = 8
Use Arctan to find angles OCD and OBD.
Angle OCD =
Angle OBD =
Since the angles at C and B were bisected,
Angle ACB = 2(33.69) = 67.38
Angle ABC = 2(26.57) = 53.13
This makes Angle CAB = 180 - 67.38 - 53.13 = 59.49
Half that gives Angle CAD = 29.75
Use Tangent to find AX.
AX = AY because they are tangent segments from the same external point.
Therefore, AC = 13 and AB = 15, approximately.
well, i coudnt quite understand the trignometric term arctan and couldnt understand how it became 7 in last.
Maybe you havce used a log table but we arent given log tables and all.
The answer is right. We did it long ago in class using herons formula or something.
Heron's formula is used to find the area of a triangle if only the sides are known. I'm not sure how that would fit in this situation unless the question were ammended to find the area after we find AB and AC.