Find the volume of a box as a function of the width of base of the box?

If 12,000 cm^2 of material is available to make a box with a square base and an open top, find the volume of the box as a function of the width if the base of the box

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- Sep 28th 2008, 06:09 PMrealintegerzVolume of a box?
Find the volume of a box as a function of the width of base of the box?

If 12,000 cm^2 of material is available to make a box with a square base and an open top, find the volume of the box as a function of the width if the base of the box - Sep 28th 2008, 07:04 PMJhevon
did you draw a diagram? (see the attached).

let the width of the base be $\displaystyle x$ and the height of the box be $\displaystyle y$

thus the volume (length times width times height) is given by

$\displaystyle V = x^2 y$

Now we know the surface area is 12000, this is the sum of the areas of all the faces, so

$\displaystyle 12000 = \underbrace{x^2}_{\text{area of base}} + \underbrace{4xy}_{\text{area of the 4 sides}}$

that is $\displaystyle 12000 = x^2 + 4xy$

now can you answer the problem? - Sep 28th 2008, 07:13 PMSoroban
Hello, realintegerz!

Quote:

If 12,000 cm² of material is available to make a box

with a square base and an open top, find the volume of the box

as a function of the width of the base of the box.

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Let $\displaystyle x$ = side of the square base.

Let $\displaystyle h$ = height of the box.

The panels comprising the box is made up of:

. . a base with area $\displaystyle x^2$

. . and four sides with area $\displaystyle xh$ each.

The total surface area is: .$\displaystyle x^2 + 4xh$

We are told that the total surface area will be 12,000 cm².

So we have: .$\displaystyle x^2 + 4xh \:=\:12,\!000 \quad\Rightarrow\quad h \:=\:\frac{12,\!000-x^2}{4x}$ .[1]

The volume of the box is: .$\displaystyle V \;=\;x^2h$

Substitute [1]: .$\displaystyle V \;=\;x^2\left(\frac{12,\!000-x^2}{4x}\right) \quad\Rightarrow\quad \boxed{V \;=\;\frac{1}{4}(12,\!000x - x^3)}$