Note: Figure not drawn to scale
In the figure, what is the area of the square with the darken borders?
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In the figure, what is the area of the inner square?Code:2 1 *-----------*-----* 1 | * * | | * * | * * | 2 |* * | | * *| 2 | * * | * * | | * * | 1 *-----*-----------* 1 2
It is a square within a square.
. . The four right triangles are congruent.
In a right triangle, the legs are 1 and 2.
. . Hence, the hypotenuse is
Therefore, the area of the inner square is: . square units.
Area of outside square=9
Now find the area of the triangles
they all have an area of 1
so all triangles put together have an area of 4
the area of the inside square is 5
instead of using pythagoras, you could just understand that the area of a right triangle is (length x height)/2