in a quadrilateral ABCD, angle ABC=40 degrees, angle BCD=100 degrees and angle CDA= 60 degrees. E is a point BC such that AE bisects the angle BAD. Find the size of the angle AED if angle BCA=44 degrees
thanx
Internal angles in a quadrilateral add up to 360
So angle DAB = 160
This is bisected by line to E so
angle DAE = angle BAE = 80
From second diagram angle DAC = 180 - 60 - 56 = 64
angle CAE = angle DAE - angle DAC = 80 - 64 = 16
angle AEC = 180 - 16 - 44 = 120
Thinking of rest
Stuck on rest. Needs either angle ADE or angle DEC or angle BED
If length of AB = length of AD I have an answer