Given: A(–2,2), B(6,5), C(4,0), D(–4,–3) Prove: ABCD is a parallelogram but not a rectangle.
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Originally Posted by magentarita Given: A(–2,2), B(6,5), C(4,0), D(–4,–3) Prove: ABCD is a parallelogram but not a rectangle. ABCD is a parallelogram ---> 1. lengths AB=CD 2. lengths AD=BC Or in terms of vectors : $\displaystyle \overrightarrow{AB}=\overrightarrow{DC}$ A sketch can make you understand why I chose these letters.
Originally Posted by Moo ABCD is a parallelogram ---> 1. lengths AB=CD 2. lengths AD=BC Or in terms of vectors : $\displaystyle \overrightarrow{AB}=\overrightarrow{DC}$ A sketch can make you understand why I chose these letters. Thanks for the tip.
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