PRAT are P(a,b)
R(a,b + 3), A(a + 3,b + 4), and T(a + 6,b + 2). Prove that segment RA is parallel to segment PT.

2. Originally Posted by magentarita

PRAT are P(a,b)

R(a,b + 3), A(a + 3,b + 4), and T(a + 6,b + 2). Prove that segment RA is parallel to segment PT.

You need to show that the slopes of RA and PT are equal.

Slope of RA: $\frac{b+4-(b+3)}{a+3-a}=\frac{1}{3}$

Slope of PT: $\frac{b+2-b}{a+6-a}=\frac{2}{6}=\frac{1}{3}$

3. ## I see...

Originally Posted by masters
You need to show that the slopes of RA and PT are equal.

Slope of RA: $\frac{b+4-(b+3)}{a+3-a}=\frac{1}{3}$

Slope of PT: $\frac{b+2-b}{a+6-a}=\frac{2}{6}=\frac{1}{3}$
I understand now but the question did not say to show that the slopes of RA and PT are equal.

Thanks

4. No but that's what "parallel" means. Think about it.