The coordinates of quadrilateral PRAT are P(a,b) R(a,b + 3), A(a + 3,b + 4), and T(a + 6,b + 2). Prove that segment RA is parallel to segment PT.
Follow Math Help Forum on Facebook and Google+
Originally Posted by magentarita The coordinates of quadrilateral PRAT are P(a,b) R(a,b + 3), A(a + 3,b + 4), and T(a + 6,b + 2). Prove that segment RA is parallel to segment PT. You need to show that the slopes of RA and PT are equal. Slope of RA: $\displaystyle \frac{b+4-(b+3)}{a+3-a}=\frac{1}{3}$ Slope of PT: $\displaystyle \frac{b+2-b}{a+6-a}=\frac{2}{6}=\frac{1}{3}$
Originally Posted by masters You need to show that the slopes of RA and PT are equal. Slope of RA: $\displaystyle \frac{b+4-(b+3)}{a+3-a}=\frac{1}{3}$ Slope of PT: $\displaystyle \frac{b+2-b}{a+6-a}=\frac{2}{6}=\frac{1}{3}$ I understand now but the question did not say to show that the slopes of RA and PT are equal. Thanks
No but that's what "parallel" means. Think about it.
View Tag Cloud