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  1. #1
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    Vector question

    URGENT!URGENT!URGENT!URGENT!URGENT!URGENT!URGENT!

    A dog has an initial position (20,3) and a velocity vector (0,-2)
    A cat has an initial position (5,6) and a velocity vector (1,1)

    Find the position vector of the cat relative to the dog ie DC
    Last edited by rhettfraser; September 18th 2008 at 08:24 PM.
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  2. #2
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    Hello, rhettfraser!

    A dog has an initial position (20,3) and a velocity vector \langle0,-2\rangle.

    A cat has an initial position (5,6) and a velocity vector \langle1,1\rangle.

    Find the position vector of the cat relative to the dog, i.e. \overrightarrow{DC}

    At time t, the cat's position vector is: \vec C \:=\: \langle 5+t,\:6+t\rangle

    . . and the dog's position vector is: \vec D \:=\:\langle 20,\:3-2t\rangle


    Therefore: . \overrightarrow{DC} \;=\;\bigg\langle(5+t) - 20,\;(6+t) - (3-2t)\bigg\rangle \;=\;\langle t-15,\:3t+3\rangle

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  3. #3
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    Thankyou for helping

    How would I use this to show that if d is the distance between the animals at any time (t) then

    d2 = 10t2 12t + 234
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  4. #4
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    Quote Originally Posted by rhettfraser View Post
    Thankyou for helping

    How would I use this to show that if d is the distance between the animals at any time (t) then

    d2 = 10t2 12t + 234
    d = magnitude of vector DC.
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  5. #5
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    Quote Originally Posted by rhettfraser View Post
    URGENT!URGENT!URGENT!URGENT!URGENT!URGENT!URGENT!

    A dog has an initial position (20,3) and a velocity vector (0,-2)
    A cat has an initial position (5,6) and a velocity vector (1,1)

    Find the position vector of the cat relative to the dog ie DC
    Are you sure this is not a question about pursuit curves?

    RonL
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