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A dog has an initial position (20,3) and a velocity vector (0,-2)
A cat has an initial position (5,6) and a velocity vector (1,1)
Find the position vector of the cat relative to the dog ie DC
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A dog has an initial position (20,3) and a velocity vector (0,-2)
A cat has an initial position (5,6) and a velocity vector (1,1)
Find the position vector of the cat relative to the dog ie DC
Hello, rhettfraser!
A dog has an initial position $\displaystyle (20,3)$ and a velocity vector $\displaystyle \langle0,-2\rangle.$
A cat has an initial position $\displaystyle (5,6)$ and a velocity vector $\displaystyle \langle1,1\rangle.$
Find the position vector of the cat relative to the dog, i.e. $\displaystyle \overrightarrow{DC}$
At time $\displaystyle t$, the cat's position vector is: $\displaystyle \vec C \:=\: \langle 5+t,\:6+t\rangle$
. . and the dog's position vector is: $\displaystyle \vec D \:=\:\langle 20,\:3-2t\rangle$
Therefore: .$\displaystyle \overrightarrow{DC} \;=\;\bigg\langle(5+t) - 20,\;(6+t) - (3-2t)\bigg\rangle \;=\;\langle t-15,\:3t+3\rangle$