Let the side of the triangle be , the side of the square be , and the radius of the circle be .Originally Posted bywardreese

Then the area of the equilateral triangle (by Herons formula - google for

it if you don't know it) is:

The area of the circle is:

,

and the area of the square is:

.

We are told that:

which allows us to write and in terms of .

We are also told that:

which when we replace and with what they are in terms of we are left with

a single linear equation for which is trivial to solve.

RonL