1. ## Geometry Triangles

I was working on a problem. I know that I am supposed to solve for the unknown. I just don't know what exactly the unknown is.

Here is the problem-

I can look out my window and see the top of a tower. On the map, I see that it is 2 miles away. I read somewhere that the tower is 500 feet tall. As I look at the tower, I see that the top leaves of a tree sometimes get in the way of the top of the tower. The tree is 50 yards from where I sit. How tall is the tree?

How do I put this problem into an equation and what is the equation?

Thanks for all potential help.

2. Hello,
Originally Posted by KevinVM20
I was working on a problem. I know that I am supposed to solve for the unknown. I just don't know what exactly the unknown is.

Here is the problem-

I can look out my window and see the top of a tower. On the map, I see that it is 2 miles away. I read somewhere that the tower is 500 feet tall. As I look at the tower, I see that the top leaves of a tree sometimes get in the way of the top of the tower. The tree is 50 yards from where I sit. How tall is the tree?

How do I put this problem into an equation and what is the equation?

Thanks for all potential help.
Do you know how to use the Intercept theorem ?

3. no

4. Hello, KevinVM20!

. . the unknown is obviously the height of the tree.

I can look out my window and see the top of a tower.
On the map, I see that it is 2 miles away.
I read somewhere that the tower is 500 feet tall.
As I look at the tower, I see that the top leaves of a tree
sometimes get in the way of the top of the tower. **
The tree is 50 yards from where I sit.
How tall is the tree?
** I assume this means that the top of tree lines up
. . with the line-of-sight to the top of the tower.

We further assume that your eye and the base of the tower are at the same height.

Let $h$ = height of the tree (in feet).
Change all units to feet.
Code:
                              *
*   |
*       |
*           | 500
*   |h          |
*       |           |
* - - - - - * - - - - - *
: -  150  - :
: - - - 10,560  - - - - :

From the two similar right triangles, we have: . $\frac{h}{150} \:=\:\frac{500}{10,560}$

Therefore: . $h \;=\;\frac{75,000}{10,560} \;=\;\frac{625}{88} \;\approx\;7.1\text{ feet}$

5. Thank you very much Soroban! I now have a better understanding.

Originally Posted by Soroban
Hello, KevinVM20!

. . the unknown is obviously the height of the tree.

** I assume this means that the top of tree lines up
. . with the line-of-sight to the top of the tower.

We further assume that your eye and the base of the tower are at the same height.

Let $h$ = height of the tree (in feet).
Change all units to feet.
Code:
                              *
*   |
*       |
*           | 500
*   |h          |
*       |           |
* - - - - - * - - - - - *
: -  150  - :
: - - - 10,560  - - - - :

From the two similar right triangles, we have: . $\frac{h}{150} \:=\:\frac{500}{10,560}$

Therefore: . $h \;=\;\frac{75,000}{10,560} \;=\;\frac{625}{88} \;\approx\;7.1\text{ feet}$