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Math Help - Right Triangles...Help!

  1. #1
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    Right Triangles...Help!

    Idk what to do, I made a triangle for the problem, but when it came to angle of elevation im clueless...help?

    The rim of a basketball hoop is 10ft above the ground. The free-throw line is 15 feet from the basket rim. If the eyes are of a basketball player are 6 feet above the ground, what is the angle of elevation of the players line of sight when shooting a free throw to the rim of a basket?


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    Quote Originally Posted by topaz192 View Post
    Idk what to do, I made a triangle for the problem, but when it came to angle of elevation im clueless...help?

    The rim of a basketball hoop is 10ft above the ground. The free-throw line is 15 feet from the basket rim. If the eyes are of a basketball player are 6 feet above the ground, what is the angle of elevation of the players line of sight when shooting a free throw to the rim of a basket?


    refer to the diagram below. you want to find the angle x

    think "trig ratio." you have the opposite side and the adjacent side to the angle x

    can you continue?
    Attached Thumbnails Attached Thumbnails Right Triangles...Help!-tris.bmp  
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    So all I do is TAN = 10 / 15? put that in the calculator and thats it?
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    Quote Originally Posted by topaz192 View Post
    So all I do is TAN = 10 / 15? put that in the calculator and thats it?
    you didn't look at my diagram, did you? there is no 10 anymore. please view the diagram i posted
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    Sorry, I assumed it was still 10.
    Why is it now 4?

    TAN = 4 / 15
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    Quote Originally Posted by topaz192 View Post
    Sorry, I assumed it was still 10.
    Why is it now 4?

    TAN = 4 / 15
    first off, trig functions do not stand alone. you cannot just have tan you must have tan(something). in this case, the something is x

    note the modification i made to your original diagram. the broken red line is the base of the triangle we are working with. it is 6 feet off the ground, so we only go 4 more feet to hit the rim. this forms the height of our right-triangle

    so you have tan(x) = 4/15 and now we continue
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  7. #7
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    Oh okay I see what you're saying.

    So in the end it'll be about 14.9 degrees.
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    Quote Originally Posted by topaz192 View Post
    Oh okay I see what you're saying.

    So in the end it'll be about 14.9 degrees.
    yes
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  9. #9
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    Thank you for your time! Now I understand how to solve problems like this! Yay!
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