# Right Triangles...Help!

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• Aug 25th 2008, 05:33 PM
topaz192
Right Triangles...Help!
Idk what to do, I made a triangle for the problem, but when it came to angle of elevation im clueless...help?

The rim of a basketball hoop is 10ft above the ground. The free-throw line is 15 feet from the basket rim. If the eyes are of a basketball player are 6 feet above the ground, what is the angle of elevation of the players line of sight when shooting a free throw to the rim of a basket?

http://i20.photobucket.com/albums/b2..._188/math2.jpg
• Aug 25th 2008, 05:42 PM
Jhevon
Quote:

Originally Posted by topaz192
Idk what to do, I made a triangle for the problem, but when it came to angle of elevation im clueless...help?

The rim of a basketball hoop is 10ft above the ground. The free-throw line is 15 feet from the basket rim. If the eyes are of a basketball player are 6 feet above the ground, what is the angle of elevation of the players line of sight when shooting a free throw to the rim of a basket?

http://i20.photobucket.com/albums/b2..._188/math2.jpg

refer to the diagram below. you want to find the angle x

think "trig ratio." you have the opposite side and the adjacent side to the angle x

can you continue?
• Aug 25th 2008, 05:46 PM
topaz192
So all I do is TAN = 10 / 15? put that in the calculator and thats it?
• Aug 25th 2008, 05:50 PM
Jhevon
Quote:

Originally Posted by topaz192
So all I do is TAN = 10 / 15? put that in the calculator and thats it?

you didn't look at my diagram, did you? there is no 10 anymore. please view the diagram i posted
• Aug 25th 2008, 05:53 PM
topaz192
Sorry, I assumed it was still 10.
Why is it now 4?

TAN = 4 / 15
• Aug 25th 2008, 06:03 PM
Jhevon
Quote:

Originally Posted by topaz192
Sorry, I assumed it was still 10.
Why is it now 4?

TAN = 4 / 15

first off, trig functions do not stand alone. you cannot just have tan you must have tan(something). in this case, the something is x

note the modification i made to your original diagram. the broken red line is the base of the triangle we are working with. it is 6 feet off the ground, so we only go 4 more feet to hit the rim. this forms the height of our right-triangle

so you have tan(x) = 4/15 and now we continue
• Aug 25th 2008, 06:07 PM
topaz192
Oh okay I see what you're saying. (Giggle)

So in the end it'll be about 14.9 degrees.
• Aug 25th 2008, 06:45 PM
Jhevon
Quote:

Originally Posted by topaz192
Oh okay I see what you're saying. (Giggle)

So in the end it'll be about 14.9 degrees.

yes
• Aug 25th 2008, 06:46 PM
topaz192
Thank you for your time! Now I understand how to solve problems like this! Yay! (Wink)