Here is the problem: Show the conjecture is false by finding a counterexample. The square root of a number x is always less than x Thank You!! Please Help Me As Soon As Possible!! I am Desperate!!
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Originally Posted by purple3000 Here is the problem: Show the conjecture is false by finding a counterexample. The square root of a number x is always less than x Thank You!! Please Help Me As Soon As Possible!! I am Desperate!! how about x = 1/4 what does this have to do with geometry? how did i come up with that? i knew that 0 < x < 1 works, but if you didn't, just solve for it. you wanted $\displaystyle \sqrt x > x$
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