A boxing ring is in the shape of a square, 33 feet on each side. How far apart are the fighters when one is in the center and the other is in the corner.

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- August 2nd 2006, 05:35 PMpashahDistance
A boxing ring is in the shape of a square, 33 feet on each side. How far apart are the fighters when one is in the center and the other is in the corner.

- August 2nd 2006, 05:42 PMQuickQuote:

Originally Posted by**pashah**

therefore we find the distance from one corner to the opposite corner:

but we only want to go half that distance, so we divide that answer by 2:

so the distance from a corner to the center is about 23 feet - August 2nd 2006, 05:51 PMThePerfectHackerQuote:

Originally Posted by**pashah**

Thus,

- August 2nd 2006, 05:53 PMQuick
here's a diagram of what I'm talking about (note: x and y are boxers)(also note: it's supposed to be a square):

Code:

-------x

| / |

| / | a

| y |

| / |

|/ |

-------

b

- August 2nd 2006, 07:58 PMc_323_h