A circular park of 20m diameter has a circular path just inside the boundary with a width of 1m.The are of the path is
15pi
17pi
19pi
25pi
I caught my error...It had a 20 m diameter...
so the area of the park would be $\displaystyle (10~m)^2\pi=100\pi~m^2$
The area of the park enclosed by the path would be $\displaystyle (10~m-1~m)^2\pi=(9~m)^2\pi=81\pi~m^2$
So then we see that the difference between the two will give us the area of the path.
$\displaystyle 100\pi~m^2-81\pi~m^2=\color{red}\boxed{19\pi~m^2}$
Does this make sense? Sorry about that; it was a mistake on my part...misread the problem.
--Chris