I want to find some arbitrary point in the plane Thank you.
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Originally Posted by MatteNoob I want to find some arbitrary point in the plane Thank you. Since 3 non-colinear points determine a plane, then try two coordinates and solve or the 3rd coordinate. 2x +4y -2z +10 = 0 Example, try x=1 and y=1, 2(1) +4(1) -2z +10 = 0 -2z = -16 z = 8 Hence, (1,1,8) is a point on the given plane.
Thank you very much. :]
Hello, MatteNoob! I want to find some arbitrary point in the plane: . The easiest points are the intercepts. .You can "eyeball" the answers! . .
or... They're just kind of staring at you in this form.
Thanks to all of you. I now understand how finding (or checking if) points (are in) the plane. :]
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