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Thread: Similiar Triangles

  1. August 3rd 2008, 04:19 PM #1
    rhettfraser
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    Similiar Triangles

    I have a triangle with it's largest side x+3 (AB). The base side is x+5 (AC). The other side doesn't have a length (BC). Point E lies on AC, AE is 5 and EC is x. Line OE is perpendicular to AB and connects to E with a length of 3. Angle ACB equals 90 degrees. Using similar triangles find x. This question was in a Yr 11 Maths Specialist assignment. The only answers I've got is -13 and -8. Please reply quickly.
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  2. August 3rd 2008, 08:23 PM #2
    Soroban
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    Hello, rhettfraser!

    There is obviously a TYPO in the problem . . .

    I have a triangle with it's largest side x+3 (AB).
    The base side is x+5 (AC). .??

    If AB \:=\:x + 3 is the longest side, how can BC\:=\:x+5 be longer?
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