In a triangle ABC, a = 2, b = 3 and tan A = √(3/5) then the value(s) of C are: A)√(10) B){√(10)}/2 C){3√(10)}/2 D){√(10)}/3
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Originally Posted by fardeen_gen In a triangle ABC, a = 2, b = 3 and tan A = √(3/5) then the value(s) of C are: A)√(10) B){√(10)}/2 C){3√(10)}/2 D){√(10)}/3 Did you mean get the value(s) of c? If your notation is to be consistent, C represents an angle and c represents a side length ..... Sine rule: . Get the value of using the given data . Then solve for B. C = 180 - A - B. Cosine rule:
Hello, fardeen_gen! In a triangle ABC: . then the value of is: Since . . Hence: . Law of Sines: . . . Hence: . Since: . , . . we have: . . . . . Law of Sines: . . .
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