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Math Help - Geometry - angles of polygons

  1. #1
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    Geometry - angles of polygons

    Find the measure of each interior angle using the given information.

    m<E = X
    m<F = (X+20)
    m<G = (X+5)
    m<H = (x-5)
    m<J = (X+10)

    ok this is how far ive gotten

    360 = m<e + m<f + m<g + m<h + m<J

    360 = X + (X+20) + (x+5) + (x-5) + (x+10)

    Now you are suppossed to combine like terms but iam not sure how to combine these

    can anyone please help
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  2. #2
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    Why do you have the sum of the interior angles equal 360?
    There are five angles. So take a look at the following webpage.
    Polygon -- from Wolfram MathWorld
    On that page look a equation (4).
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  3. #3
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    What kind of polygon is this? How can you assume that the 5 angles equal 360? If this is a quadrilateral, then the sum of the interior angles is 360. If it is a pentagon, then the sum of the interior angles is 360+180=540. And so forth. You have five interior angles given. I would assume this would be a pentagon. In this case, m<e + m<f + m<g + m<h + m<J = 540.

    Then, x + (x+20) + (x+5) + (x-5) + (x+10) = 540.

    Solve for x just like an algebra 1 problem. Then plug in x for each of your five interior angles to get your exact values.

    If there is additional information to this problem, please mention it. Good luck.
    -Andy
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