PQRSis a square and pointsEandFare outside the square so thatPQEandQRFare equilateral triangles. The size ofEQFin degree, is

(A) 60

(B) 90

(C) 120

(D) 150

(E) 180

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- July 28th 2008, 02:28 AM #1

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- July 28th 2008, 02:33 AM #2

- July 28th 2008, 02:47 AM #3

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Hello!

Please loo at the attachment to see the drawing of this problem.

With that in mind you simply add up the 90 degree angle of the square, and because both triangles are equalateral 2 x 60 degrees to get 210 degress then you take that from 360 to get the answer of 150 degrees.

Hope thats ok!