The triangle ABC is right triangled at A. Ratio of the radius of the circle circumscribed to the radius of the circle escribed to the hypotenuse is √2 : (√3 + √2). Find the angles B & C and the ratio of the two perpendicular sides of the triangle.
(This involves trigonometry, doesn't it? But where? And how?....)
radius of circle escribed to the hypotenuse=
On taking the ratio and equating with the given ratio you will get
2cos(B/2).cos(C/2) = sqrt(3)+sqrt(2) > 2(Never possible)
Hence,your question appears wrong .
Would you mind specifying the source of this question