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Math Help - Properties of Triangles(involving circumscribed, ascribed...)?

  1. #1
    Super Member fardeen_gen's Avatar
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    Properties of Triangles(involving circumscribed, ascribed...)?

    The triangle ABC is right triangled at A. Ratio of the radius of the circle circumscribed to the radius of the circle escribed to the hypotenuse is √2 : (√3 + √2). Find the angles B & C and the ratio of the two perpendicular sides of the triangle.

    (This involves trigonometry, doesn't it? But where? And how?....)
    Last edited by fardeen_gen; July 21st 2008 at 05:58 AM.
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  2. #2
    Moo
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    A Cute Angle Moo's Avatar
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    Quote Originally Posted by fardeen_gen View Post
    The triangle ABC is right triangled at A. Ratio of the radius of the circle circumscribed to the radius of the circle ascribed to the hypotenuse is √2 : (√3 + √2). Find the angles B & C and the ratio of the two perpendicular sides of the triangle.

    (This involves trigonometry, doesn't it? But where? And how?....)
    Hello,
    what is an ascribed circle ? Did you mean inscribed ?
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  3. #3
    Senior Member pankaj's Avatar
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    Quote Originally Posted by fardeen_gen View Post
    The triangle ABC is right triangled at A. Ratio of the radius of the circle circumscribed to the radius of the circle ascribed to the hypotenuse is √2 : (√3 + √2). Find the angles B & C and the ratio of the two perpendicular sides of the triangle.

    (This involves trigonometry, doesn't it? But where? And how?....)
    it appears that the ratio you have quoted is wrong.
    Circumradius= a/2

    radius of circle escribed to the hypotenuse=
    a.(cos(B/2).cos(C/2))/(cos(A/2))

    On taking the ratio and equating with the given ratio you will get
    2cos(B/2).cos(C/2) = sqrt(3)+sqrt(2) > 2(Never possible)

    Hence,your question appears wrong .

    Would you mind specifying the source of this question
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  4. #4
    Super Member fardeen_gen's Avatar
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    @Moo : Forgive the typo. Post edited.(its escribed)
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