irregular polygon

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July 16th 2008, 06:23 PM
celticcrest

Does This Work?

thanks
July 16th 2008, 07:07 PM
Soroban

Hello, celticcrest!

Could you double-check the numbers?

Quote:

I am trying to split an irregular polygon into three equal areas, width ways.

762.30 top width
752.77 bottom width
962.99 left length
962.99 right length

Total area : 728430
Perimeter: 3440.96 ??
Area of each subdivision: 242810

The perimeter is: . $762.30 + 752.77 + 962.99 + 962.99 \;=\;{\color{red}3441.05}$
July 16th 2008, 07:39 PM
meymathis

I wouldn't swear to it, but I don't think that you have given enough information to uniquely determine the quadrilateral in question. Generally, if you just give the length of 4 sides, there is a host of quadrilaterals that will fit the bill. You also gave an area, which my intuition says probably gets us down to two different quadrilaterals.

Anyway, all this to say that the problem would be much easier if you gave coordinates. You could use lat/lon or you could call the bottom left (0,0), and the bottom right ( 752.77,0) and then just give the coordinates of the other 2. I think this would be pretty straightforward to do then.
July 16th 2008, 08:04 PM
celticcrest

Thanks

Thanks. That is the problem there is no determined right angle. Only given the four lengths and the total area. None of the lengths are equal or parallel.
And with the three way split being width ways instead of length ways just makes it more difficult. Thanks anyway
July 16th 2008, 09:52 PM
wildtom

Yeah got the same problem. You had any luck solving it?
Diagram may be of some use.
area a=b=c total area : 728430 mSq subdivision area 242810 mSq

vp= 962.43m zs= 952.77m vz= 962.99m ps= 962.79m
width difference 0.2m from top to bottom
length difference 9.66m from left to right

what are the lengths of :
vx xy yz zs sr rq qp pv

basically a rectangle vpsz. with points xy on the left side
and points qr on the right side. you have to determine the
distances from the points listed above so that each
division has an equal area . creating 3 new polygons.
July 16th 2008, 10:31 PM
wildtom

Its a block of land

Hello Paul.
I have determined it is a block of land.
Look at the total area 728430 mSq . Thats 180 Acres
The size of each new polygon . 242810 mSq . Thats 60 Acres.
Its basically a rectangle. The angle is 89.43 degrees. Almost 90 degrees not quite.
By using the top boundary 762.43m and the bottom boundary of 752.77m
and the perimeter and the area
The top polygon vpqx has dimensions vp= 762.43 pq = Lies between 318.4m and 322.5m xq =759.1m vx Lies between 318.4m and 322.5m
The bottom polygon yrsz dimensions are zs=752.77m yr=755.77m zy=321.8m rs=321.1