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Thread: 5 Trig Problems

  1. July 14th 2008, 07:09 PM #1
    Macabro
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    Angry 5 Trig Problems

    moved!
    Last edited by Macabro; July 14th 2008 at 07:16 PM. Reason: wrong section
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  2. July 14th 2008, 07:17 PM #2
    topsquark
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    Quote Originally Posted by Macabro View Post
    3^{2 - 3x} = 4^{2x + 1}

    Taking the ln of both sides:
    ln \left ( 3^{2 - 3x} \right ) = ln \left ( 4^{2x + 1} \right )

    (2 - 3x)~ln(3) = (2x + 1)~ln(4)
    which is now simply a linear equation in x.

    -Dan
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