moved!
Last edited by Macabro; Jul 14th 2008 at 07:16 PM. Reason: wrong section
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Originally Posted by Macabro $\displaystyle 3^{2 - 3x} = 4^{2x + 1}$ Taking the ln of both sides: $\displaystyle ln \left ( 3^{2 - 3x} \right ) = ln \left ( 4^{2x + 1} \right )$ $\displaystyle (2 - 3x)~ln(3) = (2x + 1)~ln(4)$ which is now simply a linear equation in x. -Dan
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