
5 Trig Problems

Quote:
Originally Posted by
Macabro
$\displaystyle 3^{2  3x} = 4^{2x + 1}$
Taking the ln of both sides:
$\displaystyle ln \left ( 3^{2  3x} \right ) = ln \left ( 4^{2x + 1} \right )$
$\displaystyle (2  3x)~ln(3) = (2x + 1)~ln(4)$
which is now simply a linear equation in x.
Dan