# 5 Trig Problems

• July 14th 2008, 07:09 PM
Macabro
5 Trig Problems
moved!
• July 14th 2008, 07:17 PM
topsquark
Quote:
$3^{2 - 3x} = 4^{2x + 1}$

Taking the ln of both sides:
$ln \left ( 3^{2 - 3x} \right ) = ln \left ( 4^{2x + 1} \right )$

$(2 - 3x)~ln(3) = (2x + 1)~ln(4)$
which is now simply a linear equation in x.

-Dan