Hi!paulo1913.
Here is the solution.
Centre of the circle will be the midpoint of GH. Let coordinate of H be (x,y) then
(3+x)/2=-1
solving it we get x=-5
similarly (-2+y)/2=8
solving this we get y=18
hence the coordinate of H are (-5,18)
This is the question I am trying to solve:
A circle has centre (-1,8). If a diameter is GH and G=(3,-2), calculate the coordinates of H.
I drew a circle with the centre as (-1,8) and G as a point on the circle as (3,-2) but I don't know what to do next.
Thank you very much for the help. Could you help me with this question?
Show that the midpoint of the line segment joining (6,-1) and (-3,8) lies on the line y=-5x+11
I figured out that the coordanates are (1.5,3.5) but I am not sure how that helps show the equation....