Given right triangle ABC, construct the point N in the interior of the triangle such

Given right triangle ABC, construct the point N in the interior of the triangle such that Angle NAC = angle NCB = angle NBA.

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Originally Posted by mathwizard

Given right triangle ABC, construct the point N in the interior of the triangle such that Angle NAC = angle NCB = angle NBA.

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On each side of the triangle erect an equilateral triangle with angle opposite the side =120 degrees and the two new sides equal. Construct the circumscribed circles for each of these triangles. The point where these intersect is the required point.

RonL