Originally Posted by **dopi**

A particle of mass m kg is acted on by two forces F1 and F2 with magnitudes 3root5 newtons and root5 newtons ad drections parallel to the vectors i+2j and i-2j respectively

The particle is initially at a position given by vector 2i+j

iv calculated the cartesian components of F1 and F2

F1 = 3i+6j

F2 = i 2j

iv also calculated the cartesian component of the total force F1+F2 = (3i+6j)+(i-2j) = 4i +4j

however the part im struggling on is that now the particle is of mass 1kg and is initially at rest, i have to use newtons 2nd law to write down an equation of motion and find the position of the particle after 1second.

so far iv tried:

F=ma

F1+F2= 1a

therefore a = 4i+4j but then i dont know how to find the new posistion ...can anyonehelp thankz