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Math Help - Pythag Question

  1. #1
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    Pythag Question

    Hi,
    This question is an extract from a book which i took a photo of
    as I couldn't be bothered replicating it on the computer

    http://i116.photobucket.com/albums/o...chet/Maths.jpg

    Currently baffled as to what the answer is.
    A Nudge in the right direction will be appreciated.
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  2. #2
    Rhymes with Orange Chris L T521's Avatar
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    Quote Originally Posted by immunofort View Post
    Hi,
    This question is an extract from a book which i took a photo of
    as I couldn't be bothered replicating it on the computer

    http://i116.photobucket.com/albums/o...chet/Maths.jpg

    Currently baffled as to what the answer is.
    A Nudge in the right direction will be appreciated.
    First find the hypotenuse of \triangle ABC. Then use that hypotenuse value to help you determine the leg \overline{CD} in \triangle ADC.

    Does that give you enough info to continue on with the problem?
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  3. #3
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    errrr?

    No Sorry, didn't help me much.
    I know how to create the long version of the equation which has 2 squareroots but i cant to be able to figure the simplified version.
    More Help would be appreciated
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  4. #4
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    Hello, immunofort!

    Chris is absolutely correct . . . and he did give you a nudge, right?
    Code:
        A *
          ** * 2
          * *   *
        x *  *     * D
          *   *   *
          *    * *
        B * * * *
             1   C

    Use Pythagorus in \Delta ABC
    AC^2 \:=\:AB^2 + BC^2\quad\Rightarrow\quad AC^2 \:=\:x^2+1\quad\Rightarrow\quad AC \:=\:\sqrt{x^2+1}

    Use Pythagorus in \Delta ADC
    CD^2 + AD^2 \:=\:AC^2\quad\Rightarrow\quad CD^2 + 2^2 \:=\:(\sqrt{x^2+1})^2 \quad\Rightarrow\quad CD^2 + 4 \:=\:x^2+1

    Therefore: . CD^2 \:=\:x^2-3 \quad\Rightarrow\quad CD \:=\:\sqrt{x^2-3}

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