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Thread: Help!!

  1. July 2nd 2006, 05:02 PM #1
    luvjonandmunky
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    Exclamation Help!!

    ok this kind of problem would usually seem easy to me but for some reason i cant get it: If mAB= 4x+1 mBC=3(x-3) mAC=6x+1 then determin each: mAB, mBC, and mAC. If anyone could give me help on this it would be greatly appreciated as it is due tomorow lol. Thank you!
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  2. July 2nd 2006, 07:50 PM #2
    Soroban
    Soroban is offline
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    Hello, luvjonandmunky!

    We need a lot more information . . .

    If m(AB) \,= \,4x+1,\;m(BC) \,= \,3(x-3),\;m(AC)\,=\,6x+1
    then determine: m(AB),\;m(BC),\;m(AC).
    Can we assume that we have a triangle
    . . and those are the lengths of the three sides?

    Is x supposed to be an integer?

    Is there some relationship between the three sides?
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  3. July 8th 2006, 09:35 AM #3
    dmoran
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    Quote Originally Posted by luvjonandmunky
    ok this kind of problem would usually seem easy to me but for some reason i cant get it: If mAB= 4x+1 mBC=3(x-3) mAC=6x+1 then determin each: mAB, mBC, and mAC. If anyone could give me help on this it would be greatly appreciated as it is due tomorow lol. Thank you!
    I'm guessing, based on the looks of the notation that this is a circle. If so, Arc AB + Arc BC = Arc AC so
    4x+1+3(x-3)=6x+1
    7x-8=6x+1
    x-8=1
    x=9

    So mAB=37, mBC=18 and mAC=55.

    Dave
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